-2x² + 10x -12 = 0
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[tex] - 2 {x}^{2} + 10x - 12 = 0 \\ - - - - - - - - - - \times ( - 1) \\ {2x}^{2} - 10x + 12 = 0 \\ {x}^{2} - 5x + 6 = 0 \\ (x - 3)(x - 2) = 0 \\ x _{1} = 3 \: or \: x_{2} = 2[/tex]
[answer.2.content][tex] - 2 {x}^{2} + 10x - 12 = 0 \\ - - - - - - - - - - \times ( - 1) \\ {2x}^{2} - 10x + 12 = 0 \\ {x}^{2} - 5x + 6 = 0 \\ (x - 3)(x - 2) = 0 \\ x _{1} = 3 \: or \: x_{2} = 2[/tex]
[answer.2.content]